Motion class 9 extra questions numerical
Practice problems with solutions for CBSE/NCERT Class 9 Physics
Important Formulas
Equations of Motion:
Basic Numericals
Q1. A car travels 300 km in 5 hours. Calculate its speed in km/h and m/s.
Solution:
Q2. A train accelerates uniformly from rest to 72 km/h in 5 minutes. Calculate its acceleration in m/s².
Solution:
Intermediate Numericals
Q3. A bus moving at 40 km/h accelerates uniformly at 0.2 m/s² for 2 minutes. Find the distance traveled during this period.
Solution:
Q4. A scooter traveling at 10 m/s applies brakes and comes to rest in 5 seconds. Calculate (a) retardation (b) distance covered before stopping.
Solution:
Graph-Based Numericals
Q5. The distance-time graph for a car is shown below. Calculate:
(a) Speed during first 2 hours
(b) Average speed for entire journey
Solution:
Q6. A velocity-time graph shows:
0-5s: Uniform acceleration from 0 to 10 m/s
5-10s: Constant velocity at 10 m/s
10-15s: Uniform retardation to 0 m/s
Calculate: (a) Acceleration (b) Distance covered
Solution:
Challenging Numericals
Q7. Two cars A and B start from the same point. Car A moves north at 40 km/h and car B moves east at 30 km/h. After 2 hours, calculate:
(a) Distance between the two cars
(b) Relative velocity of car A with respect to car B
Solution:
Distance by A north = 40 × 2 = 80 km
Distance by B east = 30 × 2 = 60 km
Q8. A train 150 m long passes a pole in 5 seconds. How long will it take to pass a 250 m long platform?
Solution:
Additional Practice Questions
Q9. A car travels first 30 km at 60 km/h and next 40 km at 80 km/h. Calculate its average speed.
Q10. A stone is dropped from a height of 80 m. Calculate (a) time to reach ground (b) velocity just before hitting ground (Take g = 10 m/s²).
Q11. A body moving with 5 m/s accelerates at 2 m/s² for 10 s. Calculate the final velocity and distance covered.
A9. Total distance = 70 km
Time for first part = 30/60 = 0.5 h
Time for second part = 40/80 = 0.5 h
Average speed = 70/1 = 70 km/h
A10. (a) Using \( s = ut + \frac{1}{2}gt^2 \):
80 = 0 + 5t² → t = 4 s
(b) v = u + gt = 0 + 10×4 = 40 m/s
A11. v = u + at = 5 + 2×10 = 25 m/s
s = ut + ½at² = 5×10 + ½×2×100 = 50 + 100 = 150 m