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Force on a Current-Carrying Conductor in a Magnetic Field Class 10 NCERT Solutions

Force on a Current-Carrying Conductor in a Magnetic Field

Force on a Current-Carrying Conductor in a Magnetic Field

What is the Force on a Current-Carrying Conductor?

When a current-carrying conductor is placed in a magnetic field, it experiences a force. This phenomenon is the basis for many electrical devices, such as electric motors and galvanometers.

Force on a Straight Conductor

The force (F) experienced by a straight current-carrying conductor of length L, carrying current I, and placed in a magnetic field B is given by:

F = I L B sinθ

Where:

  • F = Force on the conductor (in Newtons).
  • I = Current in the conductor (in Amperes).
  • L = Length of the conductor (in meters).
  • B = Magnetic field strength (in Tesla).
  • θ = Angle between the current direction and the magnetic field.

Force on a Straight Conductor

Force on straight conductor

The direction of the force is given by Fleming’s Left-Hand Rule:

  • Stretch the thumb, forefinger, and middle finger of your left hand mutually perpendicular to each other.
  • Forefinger points in the direction of the magnetic field (B).
  • Middle finger points in the direction of the current (I).
  • Thumb points in the direction of the force (F).

Force on a Circular Loop

For a circular loop carrying current in a magnetic field, the force acts on each segment of the loop. The net force on the loop is zero, but it experiences a torque that tends to rotate it.

Force on a Circular Loop

Force on circular loop

The torque (τ) on a circular loop of area A, carrying current I, and placed in a magnetic field B is given by:

τ = I A B sinθ

Where:

  • τ = Torque on the loop (in Newton-meters).
  • I = Current in the loop (in Amperes).
  • A = Area of the loop (in square meters).
  • B = Magnetic field strength (in Tesla).
  • θ = Angle between the normal to the loop and the magnetic field.

Force on a Solenoid

A solenoid carrying current in a magnetic field experiences a force on each turn of the coil. The net force depends on the orientation of the solenoid relative to the magnetic field.

Force on a Solenoid

Force on solenoid

The force on a solenoid of length L, number of turns N, and carrying current I in a magnetic field B is given by:

F = N I L B sinθ

Where:

  • F = Force on the solenoid (in Newtons).
  • N = Number of turns in the solenoid.
  • I = Current in the solenoid (in Amperes).
  • L = Length of the solenoid (in meters).
  • B = Magnetic field strength (in Tesla).
  • θ = Angle between the solenoid axis and the magnetic field.

Key Points to Remember

  • The force on a current-carrying conductor in a magnetic field is given by F = I L B sinθ.
  • The direction of the force is determined by Fleming’s Left-Hand Rule.
  • A circular loop in a magnetic field experiences a torque given by τ = I A B sinθ.
  • A solenoid in a magnetic field experiences a force given by F = N I L B sinθ.
  • The force is maximum when the conductor is perpendicular to the magnetic field (θ = 90°).
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