Coordination Compounds

Coordination Compounds - Class 12 Chemistry

Class 12 Chemistry | Chapter 5

Coordination Compounds

Werner's Theory • Nomenclature • Isomerism • VBT • Crystal Field Theory

1. Werner's Theory of Coordination Compounds

Alfred Werner proposed the concept of primary and secondary valencies for metal ions in coordination compounds.

  • Primary Valency: Corresponds to the oxidation state of the central metal ion. It is non-directional, ionisable (can be precipitated), and satisfied by negative ions.
  • Secondary Valency: Corresponds to the coordination number of the central metal ion. It is directional, non-ionisable, and satisfied by negative ions or neutral molecules (ligands). Every metal has a fixed number of secondary valencies.

1.1 Double Salts vs Complex Salts

  • Double Salts: Dissociate completely into simple ions when dissolved in water. Example: Mohr's salt [FeSO4·(NH4)2SO4·6H2O], Potash alum [KAl(SO4)2·12H2O].
  • Complex Salts: Contain a complex ion that does not dissociate into simple ions in water. Example: K4[Fe(CN)6] yields 4K+ and [Fe(CN)6]4− ions, but NOT Fe2+ or CN ions.

2. Definitions of Some Important Terms

Coordination Entity: Constitutes a central metal atom or ion bonded to a fixed number of ions or molecules. Example: [CoCl3(NH3)3].
  • Central Atom/Ion: The atom/ion to which a fixed number of ions/groups are bound in a definite geometrical arrangement around it. It acts as a Lewis acid (electron pair acceptor).
  • Ligands: The ions or molecules bound to the central atom/ion. They act as Lewis bases (electron pair donors).
    • Unidentate: Donates one electron pair (e.g., Cl, H2O, NH3).
    • Didentate / Bidentate: Donates two electron pairs (e.g., ethane-1,2-diamine 'en', oxalate ion C2O42− 'ox').
    • Polydentate: Donates several electron pairs (e.g., EDTA4− is hexadentate).
    • Chelate Ligand: A di- or polydentate ligand that uses its two or more donor atoms to bind a single metal ion, forming a ring structure. Chelate complexes are more stable.
    • Ambidentate Ligand: A ligand which can ligate through two different atoms. (e.g., NO2 can bind through N or O; SCN can bind through S or N).
  • Coordination Number (C.N.): The number of ligand donor atoms to which the metal is directly bonded. (Note: A bidentate ligand counts as 2 towards C.N.).
  • Coordination Polyhedron: The spatial arrangement of the ligand atoms around the central atom (e.g., octahedral, tetrahedral, square planar).

3. IUPAC Nomenclature of Coordination Compounds

Rules for naming mononuclear coordination compounds:

  1. The cation is named first in both positively and negatively charged coordination entities.
  2. The ligands are named in an alphabetical order before the name of the central atom/ion.
  3. Names of anionic ligands end in -o (e.g., chlorido, cyanido). Neutral ligands use their common names, but there are exceptions: H2O is aqua, NH3 is ammine, CO is carbonyl, NO is nitrosyl.
  4. Prefixes di-, tri-, tetra-, etc., are used to indicate the number of individual ligands. If the ligand name itself includes a numerical prefix (e.g., ethylenediamine), the terms bis-, tris-, tetrakis- are used, and the ligand name is placed in parentheses.
  5. If the complex ion is an anion, the name of the metal ends with the suffix -ate (e.g., ferrate for iron, argentate for silver). If the complex ion is a cation or neutral, the metal name is the same as the element.
  6. The oxidation state of the metal in cation, anion or neutral coordination entity is indicated by Roman numeral in parentheses.

Examples:
[Cr(NH3)3(H2O)3]Cl3 → triamminetriaquachromium(III) chloride
K3[Fe(CN)6] → potassium hexacyanidoferrate(III)

4. Isomerism in Coordination Compounds

Isomers have the same molecular formula but different arrangements of atoms. They differ in physical and/or chemical properties.

4.1 Structural Isomerism

  • Linkage Isomerism: Arises in a coordination compound containing an ambidentate ligand. E.g., [Co(NH3)5(NO2)]Cl2 (with NO2 bonded through N) and [Co(NH3)5(ONO)]Cl2 (bonded through O).
  • Coordination Isomerism: Arises from the interchange of ligands between cationic and anionic entities of different metal ions present in a complex. E.g., [Co(NH3)6][Cr(CN)6] and [Cr(NH3)6][Co(CN)6].
  • Ionisation Isomerism: E.g., [Co(NH3)5SO4]Br vs [Co(NH3)5Br]SO4. They give different ions in solution.
  • Solvate (Hydrate) Isomerism: E.g., [Cr(H2O)6]Cl3 (violet) vs [Cr(H2O)5Cl]Cl2·H2O (grey-green).

4.2 Stereoisomerism

  • Geometrical Isomerism: Arises in heteroleptic complexes due to different possible geometric arrangements of the ligands.
    • Square Planar (ML2X2): Can exist as cis (similar ligands adjacent to each other) or trans (opposite to each other). Examples: [Pt(NH3)2Cl2] (cis-platin is used in cancer therapy).
    • Octahedral (ML4X2): Can exist as cis and trans.
    • Octahedral (ML3X3): Forms fac (facial) and mer (meridional) isomers.
  • Optical Isomerism: Chiral molecules that are non-superimposable mirror images of each other. They are called enantiomers (dextro and laevo forms). Common in octahedral complexes involving didentate ligands like [Co(en)3]3+ or cis-[PtCl2(en)2]2+. Trans isomers are usually optically inactive due to a plane of symmetry.

5. Valence Bond Theory (VBT)

Predicts the shape and magnetic properties based on hybridization.

  • Coordination Number 4:
    • sp3 Hybridization: Tetrahedral shape. Generally with weak field ligands (e.g., [NiCl4]2−).
    • dsp2 Hybridization: Square planar shape. Generally with strong field ligands that pair up inner d-electrons (e.g., [Ni(CN)4]2−).
  • Coordination Number 6:
    • d2sp3 Hybridization: Inner orbital complex. Shape: Octahedral. Occurs when inner (n-1)d orbitals are used (usually with strong field ligands). E.g., [Co(NH3)6]3+.
    • sp3d2 Hybridization: Outer orbital complex. Shape: Octahedral. Occurs when outer nd orbitals are used (usually with weak field ligands). E.g., [CoF6]3−.
⚠️ NEET TIP: Magnetic properties (paramagnetism vs diamagnetism) tell us the number of unpaired electrons. We use this to deduce whether pairing occurred before hybridization, which reveals if it's an inner or outer orbital complex.

6. Crystal Field Theory (CFT)

Considers the metal-ligand bond to be completely ionic (electrostatic interaction). When ligands approach the central metal ion, the five degenerate d-orbitals split into two sets of different energies (Crystal Field Splitting).

6.1 Crystal Field Splitting in Octahedral Complexes

The six ligands approach along the x, y, and z axes.

  • The orbitals lying strictly on the axes (dx²-y², d) experience more repulsion and their energy is raised. This set is called eg.
  • The orbitals lying between the axes (dxy, dyz, dzx) experience less repulsion and their energy is lowered. This set is called t2g.
  • The energy difference between t2g and eg is called crystal field splitting energy, denoted by Δo.

6.2 Crystal Field Splitting in Tetrahedral Complexes

The four ligands approach between the axes.

  • The dxy, dyz, dzx (the t2 set) orbitals are raised in energy.
  • The dx²-y², d (the e set) orbitals are lowered in energy.
  • Splitting energy is smaller. Δt = (4/9) Δo. Because Δt is small, pairing does not usually occur (mostly high spin complexes).

6.3 Spectrochemical Series

Arrangement of ligands in order of increasing field strength:
I < Br < SCN < Cl < S2− < F < OH < C2O42− < H2O < NCS < edta4− < NH3 < en < CN < CO

  • Weak field ligands (e.g., Halogens): Cause small splitting (Δo < P, pairing energy). Electrons do not pair up in t2g but enter eg. Form High spin complexes.
  • Strong field ligands (e.g., CN, CO): Cause large splitting (Δo > P). Electrons pair up in t2g before filling eg. Form Low spin complexes.

6.4 Colour in Coordination Compounds

Colour is due to the excitation of an electron from lower energy d-orbital (e.g., t2g) to a higher energy d-orbital (e.g., eg). This is called d-d transition.

If ligands are removed, splitting disappears, and the substance becomes colourless (e.g., when anhydrous CuSO4 loses water, it becomes white).

7. Bonding in Metal Carbonyls

The metal-carbon bond in metal carbonyls possess both s and p character. The ligand CO is a pi-acid ligand.

Synergic Bonding: The M-C sigma bond is formed by donation of lone pair of electrons on the carbonyl carbon into a vacant orbital of the metal. The M-C pi bond is formed by the donation of a pair of electrons from a filled d orbital of metal into the vacant antibonding pi* orbital of carbon monoxide.

This electron transfer from metal to ligand is called back bonding. This creates a synergic effect which strengthens the bond between CO and the metal.

🎓 NEET Previous Year Questions

Q1. [NEET 2022] Find the correct pair of ambidentate ligands amongst: A. CN⁻ B. SCN⁻ C. C2O4²⁻ D. H2O.
Answer Ambidentate ligands possess two different donor atoms and can coordinate through either of them. Cyanide (CN⁻) can bind through C or N. Thiocyanate (SCN⁻) can bind through S or N. Correct pair is A and B.
Q2. [NEET 2021] The correct IUPAC name for [Pt(en)2Cl(NO2)]²⁺ is:
Answer Ligands in alphabetical order: chlorido, bis(ethane-1,2-diamine), nitrito-N. Metal is Platinum with O.S. = 2 (charge on complex) - (0) - (-1) - (-1) = +4. Chloridobis(ethane-1,2-diamine)nitrito-N-platinum(IV) ion.
Q3. [NEET 2020] Anisole on cleavage with HI yields: (Wait, question swapped from organic, let's use a real coord comp PYQ). The calculated spin only magnetic moment of Cr²⁺ ion is:
Answer Cr (24) is 3d⁵ 4s¹. Cr²⁺ is 3d⁴. Number of unpaired electrons n=4. μ = √[4(4+2)] = √24 ≈ 4.90 BM.
Q4. [NEET 2019] What is the correct electronic configuration of the central atom in K4[Fe(CN)6] based on crystal field theory?
Answer Oxidation state of Fe is +2. Fe²⁺ is a 3d⁶ system. CN⁻ is a strong field ligand, so Δo > P. All 6 electrons pair up in the lower t2g orbitals. Configuration: t2g⁶ eg⁰.
Q5. [NEET 2018] Which of the following complexes is optically active? (a)[Pt(NH3)2Cl2] (b)[Co(NH3)5Cl]²⁺ (c)trans-[Co(en)2Cl2]⁺ (d)cis-[Co(en)2Cl2]⁺
Answer Optically active means lacking a plane of symmetry. Square planar and trans isomers usually have a plane of symmetry and are inactive. The cis form of [M(en)2X2] is non-superimposable on its mirror image. (d) cis-[Co(en)2Cl2]⁺.

💡 Rapid Revision

  • Werner Theory: Primary valency = Oxidation state (ionizable). Secondary valency = Coordination number (non-ionizable, directional).
  • Strong field ligands pair up inner d-electrons leading to low-spin/inner orbital complexes (d²sp³). Weak field ligands don't force pairing, leading to high-spin/outer orbital complexes (sp³d²).
  • Δt = (4/9) Δo. Because Δt is small, tetrahedral complexes are rarely low-spin.
  • Carbonyls (CO) exhibit synergic bonding (sigma donation to metal + pi back-bonding from metal), creating highly stable complexes.
Numericals & Solutions - Coordination Compounds - Class 12 Chemistry

CLASS 12 CHEMISTRY | NCERT SOLUTIONS

Chapter 5 — Coordination Compounds

22 Solved Questions — IUPAC Naming, VBT, CFT & Isomerism

Note: This chapter emphasizes applying rules (IUPAC nomenclature, Valence Bond Theory for shape/magnetism, Crystal Field Theory for splitting/colour) rather than mathematical numericals.

📝 IUPAC Nomenclature (Q1 – Q6)

3 MarksQ1. Write the IUPAC names of the following coordination compounds: (a) [Co(NH₃)₆]Cl₃ (b) [Pt(NH₃)₂Cl(NH₂CH₃)]Cl (c) [Ti(H₂O)₆]³⁺
✓ Solution
(a) Ligands: 6 ammine. Metal: Cobalt. O.S: x + 6(0) = +3 ⇒ x = +3. Anion: chloride.
Name: Hexaamminecobalt(III) chloride
(b) Ligands: 2 ammine, 1 chlorido, 1 methanamine. Alphabetical: ammine, chlorido, methanamine. Metal: Platinum. O.S: x + 2(0) - 1 + 0 = +1 ⇒ x = +2.
Name: Diamminechlorido(methanamine)platinum(II) chloride
(c) Ligands: 6 aqua. Metal: Titanium. O.S: x + 6(0) = +3 ⇒ x = +3. It's an ion.
Name: Hexaaquatitanium(III) ion
3 MarksQ2. Write the IUPAC names of: (a) K₄[Fe(CN)₆] (b) K₃[Fe(C₂O₄)₃] (c) K₂[PdCl₄]
✓ Solution
(a) Cation: Potassium. Complex is Anionic (-4 charge). Ligands: 6 cyanido. Metal: ferrate. O.S: x + 6(-1) = -4 ⇒ x = +2.
Name: Potassium hexacyanidoferrate(II)
(b) Cation: Potassium. Complex is Anionic (-3 charge). Ligands: 3 oxalato. Metal: ferrate. O.S: x + 3(-2) = -3 ⇒ x = +3.
Name: Potassium trioxalatoferrate(III)
(c) Cation: Potassium. Complex is Anionic (-2 charge). Ligands: 4 chlorido. Metal: palladate. O.S: x + 4(-1) = -2 ⇒ x = +2.
Name: Potassium tetrachloridopalladate(II)
3 MarksQ3. Write the formulas for the following coordination compounds: (a) Tetraammineaquachloridocobalt(III) chloride (b) Potassium tetrahydroxidozincate(II) (c) Potassium trioxalatoaluminate(III)
✓ Solution
(a) Complex cation: [Co(NH₃)₄(H₂O)Cl]²⁺. (Since Co is +3, ligands: 0, 0, -1. Net = +2). Anion is Cl⁻. So we need 2 Cl⁻.
Formula: [Co(NH₃)₄(H₂O)Cl]Cl₂
(b) Complex anion: [Zn(OH)₄]²⁻. (Zn=+2, 4OH⁻=-4. Net=-2). Cation is K⁺. We need 2 K⁺.
Formula: K₂[Zn(OH)₄]
(c) Complex anion: [Al(C₂O₄)₃]³⁻. (Al=+3, 3ox=-6. Net=-3). Cation is K⁺. We need 3 K⁺.
Formula: K₃[Al(C₂O₄)₃]
2 MarksQ4. Write the formula of Dichloridobis(ethane-1,2-diamine)platinum(IV) nitrate.
✓ Solution
Central atom: Pt(IV).
Ligands: 2 chlorido (Cl⁻), 2 ethane-1,2-diamine (en, neutral).
Charge on complex sphere = +4 (from Pt) + 2(-1) (from Cl) + 0 (from en) = +2.
Anion is nitrate (NO₃⁻). To balance +2 charge, we need two NO₃⁻ ions.
Formula: [PtCl₂(en)₂](NO₃)₂
2 MarksQ5. Indicate the types of isomerism exhibited by the complex [Co(NH₃)⁵(NO₂)](NO₃)₂.
✓ Solution
1. Ionisation Isomerism: Because NO₂⁻ and NO₃⁻ can exchange places. E.g., [Co(NH₃)⁵(NO₃)](NO₃)(NO₂).
2. Linkage Isomerism: Because the NO₂⁻ group is an ambidentate ligand. It can bind through N (nitrito-N) or O (nitrito-O), forming [Co(NH₃)⁵(ONO)](NO₃)₂.
2 MarksQ6. Specify the oxidation numbers of the metals in the following coordination entities: (a) [Co(H₂O)(CN)(en)₂]²⁺ (b) [PtCl⁴]²⁻
✓ Solution
(a) [Co(H₂O)(CN)(en)₂]²⁺
Let ox state of Co be x. H₂O is neutral (0), CN is -1, en is neutral (0).
x + 0 + (-1) + 2(0) = +2 ⇒ x = +3.
(b) [PtCl⁴]²⁻
x + 4(-1) = -2 ⇒ x = -2 + 4 = +2.

💡 VBT & CFT Reasoning (Q7 – Q14)

3 MarksQ7. Using valence bond theory, explain the geometry and magnetic behaviour of [Co(NH₃)₆]³⁺. (Atomic number of Co = 27)
✓ Solution
Co (Z=27) : [Ar] 3d⁷ 4s².
Co³⁺ : [Ar] 3d⁶.
NH₃ is a strong field ligand for Co³⁺. It forces the pairing of electrons in the 3d orbitals.
The 6 electrons pair up in three 3d orbitals, leaving two 3d orbitals vacant (d²sp³ hybridization).
The six vacant d²sp³ hybrid orbitals accept electron pairs from six NH₃ molecules.
Geometry: Octahedral (due to d²sp³).
Magnetic Behaviour: Diamagnetic (because all electrons are paired).
3 MarksQ8. [NiCl⁴]²⁻ is paramagnetic while [Ni(CO)⁴] is diamagnetic though both are tetrahedral. Why?
✓ Solution
[NiCl⁴]²⁻: Ni is in +2 oxidation state (3d⁸). Cl⁻ is a weak field ligand, so no pairing of 3d electrons occurs. Two unpaired electrons remain. Hybridization is sp³ (tetrahedral geometry). So it is paramagnetic.
[Ni(CO)⁴]: Ni is in 0 oxidation state (3d⁸ 4s²). CO is a very strong field ligand. It causes the 4s electrons to be pushed back and paired in the 3d orbitals, making it 3d¹⁰. Since all d-orbitals are full, no unpaired electrons exist. Hybridization is sp³. So it is diamagnetic.
Both are sp³ (tetrahedral), but differ in pairing due to ox. state and ligand strength.
3 MarksQ9. Explain the hybridization, geometry, and magnetic property of [Fe(CN)₆]⁴⁻.
✓ Solution
In [Fe(CN)₆]⁴⁻, Fe is in +2 oxidation state (3d⁶).
CN⁻ is a strong field ligand. It causes pairing of electrons in 3d orbital against Hund's rule.
Configuration becomes 3d⁶ with all 6 electrons completely paired in three 3d orbitals. Two inner 3d orbitals are vacant.
Hybridization: d²sp³ (Inner orbital complex).
Geometry: Octahedral.
Magnetic Property: Diamagnetic (n=0, no unpaired electrons).
3 MarksQ10. Discuss the nature of bonding in metal carbonyls.
✓ Solution
The metal-carbon bond possesses both σ and π character. This is called synergic bonding.
1. σ-bond: Formed by the donation of a lone pair of electrons from the carbonyl carbon into a vacant orbital of the metal.
2. π-bond (Back bonding): Formed by the donation of a pair of electrons from a filled d-orbital of the metal into the vacant antibonding π* orbital of carbon monoxide. The synergic effect strengthens the bond between CO and the metal atom.
2 MarksQ11. Draw figure to show the splitting of d orbitals in an octahedral crystal field.
✓ Solution
In an octahedral field, the 5 degenerate d-orbitals split into two sets:
1. eg set (higher energy): dx²-y², d orbitals (point directly at ligands along the axes).
2. t2g set (lower energy): dxy, dyz, dzx orbitals (point between the axes).
The energy gap between them is denoted by Δo. (Note: sketch involves 5 degenerate lines splitting into 2 lines above and 3 lines below a barycenter).
3 MarksQ12. What is spectrochemical series? Explain the difference between a weak field ligand and a strong field ligand.
✓ Solution
The arrangement of ligands in order of their increasing field strengths (ability to split d orbitals) is called the spectrochemical series.
Weak field ligands: Cause small crystal field splitting (Δo < P, pairing energy). Electrons do not pair up in lower orbitals easily; they enter higher orbitals forming High-spin complexes.
Strong field ligands: Cause large crystal field splitting (Δo > P). Electrons pair up in lower energy orbitals before entering higher ones, forming Low-spin complexes.
3 MarksQ13. Predict the number of unpaired electrons in the square planar [Pt(CN)⁴]²⁻ ion.
✓ Solution
Pt is in +2 oxidation state. Pt²⁺ has a 5d⁸ configuration.
For entirely 4d and 5d series elements, the crystal field splitting is very large (even with weak ligands, but here we have CN⁻ which is a strong ligand anyway).
Therefore, pairing occurs. Square planar uses dsp² hybridization. The 8 electrons pair up in four inner d-orbitals, leaving one d-orbital empty for hybridization.
Number of unpaired electrons = 0. (It is diamagnetic).
2 MarksQ14. Why is [Co(H₂O)₆]³⁺ a high spin complex whereas [Co(CN)₆]³⁻ is a low spin complex?
✓ Solution
H₂O is a weak field ligand (Δo < P). It does not cause forced pairing of 3d electrons in Co³⁺ (3d⁶), so it occupies outer 4d orbitals (sp³d²), resulting in a high spin complex (4 unpaired e⁻).
CN⁻ is a strong field ligand (Δo > P). It causes pairing of the six 3d electrons (t2g⁶), leaving inner orbitals free for d²sp³ hybridization. No unpaired electrons remain, resulting in a low spin complex.

📈 Isomerism & Applications (Q15 – Q22)

3 MarksQ15. Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes: (a) K₃[Co(C₂O₄)₃] (b) cis-[Cr(en)₂Cl₂]Cl
✓ Solution
(a) K₃[Co(C₂O₄)₃]:
O.S: K is +1. Oxalate is -2. 3(+1) + x + 3(-2) = 0 ⇒ x = +3.
C.N.: Oxalate is bidentate. 3 × 2 = 6.
d-orbital occ.: Co³⁺ is 3d⁶. Oxalate acts as a strong ligand here, pairing occurs: t2g⁶ eg⁰.
(b) cis-[Cr(en)₂Cl₂]Cl:
O.S: x + 2(0) + 2(-1) - 1(from outer Cl) = 0 ⇒ x = +3.
C.N.: en is bidentate (2×2=4), Cl is unidentate (2). Total C.N. = 6.
d-orbital occ.: Cr³⁺ is 3d³. It will be t2g³ eg⁰.
3 MarksQ16. Draw the structures of optical isomers of [Co(en)₃]³⁺.
✓ Solution
[Co(en)₃]³⁺ forms non-superimposable mirror images (enantiomers), typically labelled as Dextro (d or +) and Laevo (l or -) forms.
(Draw Co in center with octahedral geometry, link adjacent positions with 3 curves marked 'en').
These complexes lack a plane of symmetry, hence they are optically active.
3 MarksQ17. Explain giving two examples of complexes which show linkage isomerism.
✓ Solution
Linkage isomerism occurs when a complex contains an ambidentate ligand (can coordinate through more than one atom).
Example 1 (Nitrito): [Co(NH₃)⁵(NO₂)]Cl₂ (yellow, bonded through N) and [Co(NH₃)⁵(ONO)]Cl₂ (red, bonded through O).
Example 2 (Thiocyanato): [Pd(PPh₃)₂(NCS)₂] (bonded through N) and [Pd(PPh₃)₂(SCN)₂] (bonded through S).
3 MarksQ18. Write the formula of the following coordination compounds: (a) Iron(III) hexacyanidoferrate(II) (b) Hexaamminecobalt(III) sulphate
✓ Solution
(a) Fe(III) cation is Fe³⁺. Complex anion: [Fe(CN)₆]⁴⁻ (since Fe is +2 inside).
To balance charges (+3 and -4), we cross-multiply. We need 4 Fe³⁺ and 3 complex anions.
Formula: Fe₄[Fe(CN)₆]₃ (This is Prussian Blue).
(b) Complex cation: [Co(NH₃)₆]³⁺. Anion: Sulphate (SO₄²⁻).
To balance charges (+3 and -2), we need 2 complex cations and 3 sulphate ions.
Formula: [Co(NH₃)₆]₂(SO₄)₃
2 MarksQ19. Aqueous copper sulphate solution (blue) gives: (a) a green precipitate with aqueous potassium fluoride, and (b) a bright green solution with aqueous potassium chloride. Explain.
✓ Solution
Aqueous CuSO₄ exists as [Cu(H₂O)⁴]²⁺ (blue complex).
(a) With KF: F⁻ ligands replace H₂O to form [CuF⁴]²⁻, which is green.
(b) With KCl: Cl⁻ ligands replace H₂O to form [CuCl⁴]²⁻, which is bright green or yellow-green.
3 MarksQ20. Discuss the role of coordination compounds in (i) biological systems (ii) analytical chemistry.
✓ Solution
(i) Biological systems: Chlorophyll is a coordination compound of Magnesium. Hemoglobin (red pigment in blood) is a coordination compound of Iron(II). Vitamin B₁₂ is a coordination compound of Cobalt.
(ii) Analytical chemistry: Qualitative analysis involves forming coloured complexes. E.g., detection of Ni²⁺ using Dimethylglyoxime (DMG) to form a rosy red precipitate [Ni(DMG)₂]. EDTA is used in volumetric analysis to test water hardness (forms stable complexes with Ca²⁺ and Mg²⁺).
3 MarksQ21. Explain why [Cu(NH₃)⁴]²⁺ is a square planar complex while [NiCl⁴]²⁻ is tetrahedral.
✓ Solution
[Cu(NH₃)⁴]²⁺: Cu(II) is 3d⁹. Under the strong ligand field of NH₃, the single unpaired electron in the 3d_{x²-y²} orbital gets promoted to the 4p orbital (or hybridization alters to dsp² by using inner 3d). Experimental evidence shows it is square planar (dsp²).
[NiCl⁴]²⁻: Ni(II) is 3d⁸. Cl⁻ is a weak ligand and cannot pair the electrons or force promotion. So, outer 4s and 4p orbitals hybridize (sp³), giving a tetrahedral geometry.
3 MarksQ22. What is meant by the chelate effect? Give an example.
✓ Solution
Chelate effect: It refers to the enhanced stability of a complex system containing chelate rings (formed by multi-dentate ligands binding a central metal at multiple points) compared to the stability of a system containing corresponding monodentate ligands.
Example: [Cd(en)₂]²⁺ is far more stable than [Cd(CH₃NH₂)⁴]²⁺. The bidentate 'en' ligand forms 5-membered rings with the metal, which are geometrically and thermodynamically very stable.
✍ Score Guide — 22 Questions
All questions from NCERT Exercises covering IUPAC, VBT, CFT and Isomerism.

High-Yield Facts & Formulas: Coordination Compounds

Werner's Theory
Two types of valency: Primary (ionizable, oxidation state) and Secondary (non-ionizable, coordination number).
Coordination Entity
The central metal atom or ion and the ligands attached to it.
Central Atom
The atom/ion to which a fixed number of ions/groups are bound in a definite geometrical arrangement.
Unidentate Ligands
Bound to metal through a single donor atom. (e.g., Cl-, H2O, NH3).
Bidentate Ligands
Bound through two donor atoms. (e.g., ethane-1,2-diamine (en), oxalate (ox2-)).
Polydentate Ligands
Bound through several donor atoms. (e.g., EDTA, a hexadentate ligand).
Chelate Effect
Enhanced stability of complexes containing chelate ligands.
Ambidentate Ligand
Can ligate through two different donor atoms. (e.g., NO2-/ONO-, SCN-/NCS-).
Coordination Polyhedron
Spatial arrangement of the ligand atoms directly attached to the central atom.
Oxidation Number
Charge remaining on the central atom after all ligands are removed.
Homoleptic Complexes
Metal is bound to only one type of ligand group. (e.g., [Co(NH3)6]3+).
Heteroleptic Complexes
Metal is bound to more than one type of ligand group. (e.g., [Co(NH3)4Cl2]+).
IUPAC Nomenclature
Anionic ligands end in -o (e.g., chlorido, sulfato). Neutral keep their name (except aqua, ammine, carbonyl).
Geometrical Isomerism
Shown by square planar and octahedral complexes. Cis-trans and fac-mer isomerism.
Optical Isomerism
Chiral complexes which are non-superimposable mirror images. Common with chelating ligands in octahedral field.
Linkage Isomerism
Occurs in coordination compounds containing ambidentate ligands.
Coordination Isomerism
Interchange of ligands between cationic and anionic entities of different metal ions.
Ionization Isomerism
Yields different ions in solution despite the same formula. (e.g., [Co(NH3)5SO4]Br).
Solvate/Hydrate Isomerism
Isomers which differ by whether water is inside or outside the coordination sphere.
Valence Bond Theory Assumptions
Metal uses hybrid orbitals (sp3, dsp2, d2sp3, sp3d2) to accept electron pairs.
Strong Field Ligands (SFL)
Cause pairing of electrons and usually form inner orbital (low-spin) complexes.
Weak Field Ligands (WFL)
Do not cause pairing and usually form outer orbital (high-spin) complexes.
Crystal Field Splitting (Δ)
The energy difference between t2g and eg levels.
High-spin vs Low-spin
Low-spin: Δo > P (Pairing energy). High-spin: Δo < P.
Tetrahedral Splitting
Δt = (4/9) Δo. Orbitals split opposite to octahedral field.
Spectrochemical Series
Experimental order of ligands based on splitting power. I- < Br- ... < NH3 < CN- < CO.
Color and CFSE
Absence of splitting (or d0/d10 configuration) leads to colorless compounds.
Bonding in metal carbonyls
Characterized by synergic effect: σ donation from CO to metal and π back-bonding from metal to CO.
EDTA structure
Ethylenediaminetetraacetate. Hexadentate ligand with 2 N and 4 O donor atoms.
Effective Atomic Number (EAN)
Total electrons in central atom after coordination. Often equals noble gas atomic number (Sidgwick rule).
Stability of Complexes
Expressed by formation constant (Kf). Higher Kf means greater stability.
Application in Medicine
Cis-platin for tumors; EDTA for lead poisoning; Penicillamine for copper removal.
Grignard Reagent
RMgX. Organometallic compound where metal is directly bonded to Carbon.
Ferrocene
[Fe(η5-C5H5)2]. A sandwich-type organometallic complex.
Double Salt
Exist only in solid state and dissociate into individual ions in water. (e.g., Mohr's Salt).
Coordination Compound
Retain their identity in solution and do not dissociate into all constituent ions.
Paramagnetic criterion
Presence of at least one unpaired electron in the central metal ion.
Coordination Polymer
Complex containing metal centers linked by ligands into an infinite array.
Labile vs Inert Complexes
Labile complexes undergo fast ligand exchange; Inert complexes undergo slow exchange.
Macrocyclic Effect
Stabilization of complexes by cyclic polydentate ligands (e.g., Crown ethers).
Vitamin B12
A coordination compound of Cobalt.
Wilkinson's Catalyst
[(PPh3)3RhCl]. Used for hydrogenation of alkenes.
Outer-orbital complex
Forms when nd orbitals are used for bonding (sp3d2).
Inner-orbital complex
Forms when (n-1)d orbitals are used for bonding (d2sp3).
Spin-only formula limitations
Does not account for orbital contribution to magnetic moment (significant in some metals).
Coordination in Nature
Essential for photosynthesis, oxygen transport, and enzyme activity.
Anionic complex naming
Metal name ends in -ate (e.g., Ferrate, Platinate).
Ligand donation
Ligand must have at least one lone pair of electrons to donate.
Geometry: CN = 4
Can be Tetrahedral (sp3) or Square Planar (dsp2).
Geometry: CN = 6
Always Octahedral (d2sp3 or sp3d2).
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