Motion

Motion

Kinematics, Graphs & Equations of Motion

In-Text Questions (Page 100)

Q1. An object has moved through a distance. Can it have zero displacement?

Yes, an object can have zero displacement even if it has moved through a distance. This happens when the final position of the object coincides with its initial position (e.g., completing a full circle).

Q2. A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement at the end of 2 minutes 20 seconds?

Given: Side = 10 m, Perimeter = 40 m, Time for 1 round = 40 s.

Total Time: 2 min 20 s = 140 s.

Rounds: 140/40 = 3.5 rounds.

In 3.5 rounds, the farmer will be at the diagonally opposite corner.
Displacement = Diagonal = √(102 + 102) = √200 = 14.14 m.

In-Text Questions (Page 102)

Q1. Distinguish between Speed and Velocity.

SpeedVelocity
Distance travelled per unit time.Displacement per unit time.
Scalar Quantity (Magnitude only).Vector Quantity (Magnitude + Direction).
Always positive.Can be positive, negative, or zero.

Q2. Under what condition(s) is the magnitude of average velocity of an object equal to its average speed?

When an object moves in a straight line in a specific direction without turning back, the magnitude of displacement is equal to the distance covered. In this case, average velocity = average speed.

In-Text Questions (Page 103)

Q1. When will you say a body is in (i) uniform acceleration? (ii) non-uniform acceleration?

(i) Uniform Acceleration: If an object travels in a straight line and its velocity increases or decreases by equal amounts in equal intervals of time (e.g., Free fall).

(ii) Non-uniform Acceleration: If the velocity changes at a non-uniform rate (e.g., A car driving in traffic).

Q2. A bus decreases its speed from 80 km/h to 60 km/h in 5 s. Find the acceleration.

Given: u = 80 km/h = 22.22 m/s, v = 60 km/h = 16.66 m/s, t = 5 s.

Step 1: a = (v - u) / t
Step 2: a = (16.66 - 22.22) / 5 = -5.56 / 5
Answer: a = -1.112 m/s2 (Retardation).

In-Text Questions (Page 109)

Q1. A bus starting from rest moves with a uniform acceleration of 0.1 m/s² for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

Given: u = 0, a = 0.1 m/s2, t = 2 min = 120 s.

(a) Speed (v): v = u + at = 0 + 0.1 × 120 = 12 m/s.

(b) Distance (s): s = ut + ½at² = 0 + 0.5 × 0.1 × (120)² = 0.05 × 14400 = 720 m.

Main Textbook Exercises

Q4. A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 m/s² for 8.0 s. How far does the boat travel during this time?

Given: u = 0, a = 3 m/s², t = 8 s.

Formula: s = ut + ½at²
s = 0 + 0.5 × 3 × (8)² = 1.5 × 64 = 96 m.

Q7. A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m/s², with what velocity will it strike the ground? After what time will it strike the ground?

Given: u = 0, s = 20 m, a = 10 m/s².

(i) Final Velocity (v): v² = u² + 2as
v² = 0 + 2 × 10 × 20 = 400
v = √400 = 20 m/s.

(ii) Time (t): v = u + at
20 = 0 + 10t
t = 20/10 = 2 s.

Motion

In-depth: Graphs & Equations

1. Graphical Representation of Motion

Distance-Time Graph
  • Uniform Speed: Straight line passing through the origin. Slope gives speed.
  • Non-uniform Speed: Curved line.
  • Stationary Object: Straight line parallel to the time axis.
Velocity-Time Graph
  • Uniform Motion: Straight line parallel to the time axis. Area under the curve gives displacement.
  • Uniform Acceleration: Straight line with positive slope. Slope gives acceleration.
  • Uniform Retardation: Straight line with negative slope.

2. Equations of Motion

For numericals involving uniform acceleration, use these three equations:

1. v = u + at

Velocity-Time Relation

2. s = ut + ½at²

Position-Time Relation

3. 2as = v² - u²

Position-Velocity Relation

Where: u = initial velocity, v = final velocity, a = acceleration, t = time, s = distance/displacement.

3. Uniform Circular Motion

When an object moves in a circular path with uniform speed, its motion is called uniform circular motion.

Velocity is NOT constant: Because the direction of motion keeps changing continuously at every point. Hence, it is accelerated motion.

Formula for Speed (v):

v = (2πr) / t

Where r = radius of the circular path, t = time taken for one round.

4. Sample Problem

Problem: A train starting from a railway station and moving with uniform acceleration attains a speed of 40 km/h in 10 minutes. Find its acceleration.


Given: u = 0 (rest), v = 40 km/h = 40 × 5/18 = 11.11 m/s, t = 10 min = 600 s.

Formula: a = (v - u) / t

Solution: a = (11.11 - 0) / 600 = 0.0185 m/s².

Key Facts & Definitions

50+ Important Points to Remember

1. Scalar Quantity

Physical quantity having only magnitude (e.g., Distance, Speed).

2. Vector Quantity

Physical quantity having both magnitude and direction (e.g., Displacement, Velocity).

3. Distance

Actual path length covered by an object.

4. Displacement

Shortest distance between initial and final position.

5. Zero Displacement

Possible even if distance is not zero (e.g., returning to start).

6. Speed

Rate of change of distance (Distance/Time).

7. Velocity

Rate of change of displacement (Speed with direction).

8. Uniform Motion

Object covers equal distances in equal intervals of time.

9. Non-Uniform Motion

Object covers unequal distances in equal intervals of time.

10. Acceleration

Rate of change of velocity ((v-u)/t).

11. SI Unit of Speed

meter per second (m/s).

12. SI Unit of Acceleration

meter per second squared (m/s²).

13. Retardation

Negative acceleration (velocity decreases).

14. Average Speed

Total Distance / Total Time.

15. Average Velocity

(Initial Velocity + Final Velocity) / 2 (for uniform acceleration).

16. Odometer

Device that measures distance travelled by an automobile.

17. Speedometer

Device that measures instantaneous speed.

18. Distance-Time Graph Slope

Gives speed.

19. Velocity-Time Graph Slope

Gives acceleration.

20. Area under v-t Graph

Gives displacement.

21. Equation 1

v = u + at.

22. Equation 2

s = ut + ½at².

23. Equation 3

2as = v² - u².

24. Free Fall

Motion under gravity alone (g = 9.8 m/s²). Uniform acceleration.

25. Circular Motion

Motion along a circular path.

26. Uniform Circular Motion

Circular motion with constant speed (but changing velocity).

27. Accelerated Motion

Uniform circular motion is an accelerated motion due to change in direction.

28. 1 km/h to m/s

Multiply by 5/18.

29. 1 m/s to km/h

Multiply by 18/5.

30. Rest

Object does not change position with respect to surroundings.

31. Motion

Object changes position with respect to time.

32. Origin

Reference point to describe the position of an object.

33. Magnitude

The numerical value of a physical quantity.

34. Negative Velocity

Indicates motion in the opposite direction.

35. Area under a-t Graph

Gives Change in Velocity.

36. Speed of Sound

Approx 340 m/s in air.

37. Speed of Light

3 × 108 m/s.

38. Time Period

Time taken to complete one revolution.

39. Unit of Time

Second (s).

40. v = 2πr/t

Formula for speed in uniform circular motion.

41. Initial Velocity (u)

Velocity at t=0. 0 if starting from rest.

42. Final Velocity (v)

Velocity at time t. 0 if coming to rest.

43. Linear Motion

Motion in a straight line.

44. Angular Velocity

Rate of change of angular displacement.

45. Deceleration

Another term for retardation.

46. Constant Speed

Covering same distance every second.

47. Graph: Parallel to X-axis (d-t)

Object is at rest.

48. Graph: Parallel to X-axis (v-t)

Constant velocity (zero acceleration).

49. Instantaneous Velocity

Velocity at a specific instant of time.

50. Relative Velocity

Velocity of one object with respect to another.

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